Skipping non-business hours outside of 9-5. NDCs may or not have refills: fill_nbr = 2 is the 2nd fill (or 1st refill) , fill_nbr = 3 is the. Value a is. 005479 (1 year + 2/365 years). Timestamp datatype in redshift will stores the maximum values up to the precision of six digits in fractional seconds. Using Kafka as your data. Amazon Redshift interprets the DECADE or DECADES DATEPART based on the common calendar. 2. The default timestamp without time zone (TIMESTAMP) format is YYYY-MM-DD HH:MI:SS. Create timestampdiif function in Redshift. select min (dateid), max (dateid) from sales where dateid between 1900 and 1910; min | max -----+----- 1900 | 1910. 0. For example, if date1 equals 2022-July-04 and date2 equals 2021-July-04, you would expect a difference of one year when you use the datediff function. In the elastic resize, the cluster will be unavailable briefly. SELECT t1. DateDiff Bigint Datetime in Redshift for Min Difference. The following queries show an example of how to calculate the completion_days as the difference between eco_date and orginated_date. Sorted by: 1. 25 from dual; Results in: 2023-05-01 06:00:00 I want to convert the above SQL to redshift runnable but failed Stack OverflowThe term numeric is used generically to refer to integer, decimal, and floating-point data types. 19. The time zone can be specified as a time zone name (such as 'Africa/Kampala' or 'Singapore') or as a time zone abbreviation (such as 'UTC' or 'PDT' ). These strings can contain datetime separators (such as ' - ', ' / ', or ': ') and the following "dateparts" and. this code works but seems like the results are off by 1 day. For a complete listing of all statements run by Amazon Redshift, you can query the SVL_STATEMENTTEXT view. AWS's Redshift provides the extract function: EXTRACT ( datepart FROM { TIMESTAMP 'literal' | timestamp } ) The datepart takes various values including epoch - you can therefore extract the epoch from a timestamp e. Redshift is highly scalable and can handle spikes in workloads. Redshift provides the different types of built-in functions to perform the different operations on the data as per user requirements. Redshift utilizes structured and semi-structured data from. And only do that for one day ranges. select last_day(add_months(last_day(trunc(to_date('20230509', 'yyyymmdd'))), - 1)) + 1. answered Mar 2, 2016 at 6:53. 2. Share. state = b. 5, if diff is 8 hours - than 0. Many companies are using Amazon Redshift to analyze and transform their data. Amazon Athena provides the easiest way to run ad hoc queries for data in Amazon S3 without the need to setup or manage any servers. Then, the last_value function will take last value per row and the distinct removes all irrelevant rows from the output. This is the documentation for the Amazon Redshift Developer Guide - amazon-redshift-developer-guide/r_DATEDIFF_function. The SQL I have isSql server supports adding and subtracting on Datetime data type, so you can simply do something like this: DECLARE @StartTime datetime = '2016-05-10 02:25:34. Redshift is a little more complex and ties up more IT management on maintenance due to lack of. Instead of using SUBSTRING, pass the entire date-time field to the TO_DATE function with the MM-DD-YYYY format which encapsulates all 3 formats above. redshift datediff not working when current_timestamp is used but working when getdate() function is used. The DateDiff function used in redshift has three arguments in it, we specify the dates for which we want to find the difference. Follow edited Oct 30, 2018 at 20:07. select. Count ----- 124. to_char (current_date,'YYYYMMDD') =. 0'::character varying can simply be '0. If the first date is later than the second date, the result is positive; otherwise, the result is negative. Specifying a period is optional. Snowflake separates compute from storage, allowing for flexible pricing and configuration. Transforming date with Redshift. Push out all due dates by one week. This is the documentation for the Amazon Redshift Developer Guide - amazon-redshift-developer-guide/r_DATEDIFF_function. 有关更多信息，请参阅 日期或时间戳函数的日期部分 。. Source: Based on the solution here. Redshift will place the query in a paused state temporarily. Pramit is a Technical Content Lead at Chaos Genius. Find out key distinctions in architecture, performance, scaling, pricing—and more!Amazon Redshift accepts different date formats, including ISO date time strings. id2; Calendar table: cal, table 1 (has start. DATEDIFF determines the number of date part boundaries that are crossed between the two expressions. Of course, it doesn't make much sense to subtract a timestamp from itself, because that obviously returns 0, but I assume you just run that as a test. In the end, when comparing Amazon Redshift’s 2, 4, and 8 node DC2. You can use the Redshift date format functions to convert the string literals, integer, date/time etc to required format. Just to clarify SQL server seems to require DATEDIFF (datepart, recentDate, olderDate) as startdate and enddate are a bit nebulous. Examples. CURRENT_DATE returns the start date for the current transaction, not for the start of the current statement. This function is especially useful for calculating intervals, such as the number of days between two. など. There are two types of CASE expressions: simple and searched. The following SQL statement converts the date 02 Oct 2001 into a date data type. The data that is used by the job depends on the data type of a particular column. Secara khusus, DATEDIFF menentukan jumlah batas bagian tanggal yang dilintasi antara dua ekspresi. Elastic resize is the fasted way to resize the cluster. select *, cast ( (cast (begin_date as date) - cast (end_date as date) YEAR) as decimal (3,2)) AS year_diff from x. Modified 5 years, 6 months ago. LIMIT clauses, ORDER BY clauses, simple predicates, and complex expressions are pushed down to the connector to reduce the amount of data scanned and decrease query execution run time. date_diff("unknown", timestamp without time zone, timestamp with time zone) does not exist So I guess that current_timestamp returns a timestamp with a timezone and getdate() a timestamp without. You can name date parts in full or abbreviate them. DATE: Dates without the time part. Amazon Redshift stores these snapshots internally in Amazon S3 by using an encrypted Secure Sockets Layer (SSL) connection. The following shows the syntax of the DATEPART() function:. 000') Then use. person_id AND t1. This is a guide to Redshift join. Redshift Create Table; Redshift DateDiff; ADVERTISEMENT. Redshift querying data on dates. In my Redshift table I have 2 columns that stores timestamp values: start_date_time and end_date_time. The terms derive from the colours red and. Firstly, let's look at which data types for time series are supported by Redshift and what kind of data they can hold. The difference between 2017-11-04 00:00:00 and 2017-11-22 10:21:00. Sorted by: 1. . The date part to which to truncate the timestamp value. To define an external table in Amazon Redshift, use the CREATE EXTERNAL TABLE command. Sorted by: 1. For example, decade 201 spans from 2000-01-01 to. AUTO distribution. create user user 1 password 'md 5153 c 434 b 4 b 77 c 89 e 6 b 94 f 12 c 5393 af 5 b'; Log on to the database using the sign-in credentials. At this time, Amazon Redshift version 1. For example the result must be something like 45:15:10 Both data warehouse platforms offer online support, but Snowflake also provides 24/7 live support. 18. For example, the following code would give the number of days between date1 and date2: DATE_DIFF is great for calculating the. If you do not want to skip the rows, you will need to load the date into a VARCHAR field (which will not cause an error) and later you will need to convert the VARCHAR into a DATE. Hi Team, The formula below was built as a beastmode but would like to move it to dimensions, the backend. g. 0. 35. ADVERTISEMENT. Redshift provides 2 kinds of node resizing features: Elastic resize; Classic resize; Elastic Resize. However when i run the same logic on actual data. If you want to retain the log data, you will need to periodically copy it to other. Comparison conditions state logical relationships between two values. If you want to get 1. state and a. Now I am trying to make this query dynamic such that it can give me count for past 6 weeks something like below as an output: Count Week ------------ 124 W43 125 W42 126 W41 127 W40 128 W39 129 W38. Implementing DATEDIFF in Redshift simply computes the difference between two dates or timestamps. When you push the DATE_DIFF() function to Amazon Redshift using a Redshift ODBC connection, the Secure Agent incorrectly returns the difference values. You may also have a look at the following articles to learn more – Redshift DateDiff; Redshift Create Table; Redshift Row_NUMBER() What is AWS RedShift?I have a segment of code written in Hiveql that generates 3 columns, a index, a date, and a range of dates: drop table if exists date_list; create temporary table date_list as with seq as( selectAs I understand it DATEDIFF will return (in number of days) the difference between two sets of dates. Weekends. Compare this with RDS, which reaches 100 gibibytes to 64 TB for most database engines. Find out key distinctions in architecture, performance, scaling, pricing—and more! SELECT * FROM schemaName. Datetime types. Viewed 5k times. Improve this answer. PostgreSQL - Date Difference in Weeks. Più precisamente, DATEDIFF determina il numero di limiti di parte di data tra due espressioni. {date|timestamp} A date column, timestamp column, or an expression that implicitly converts to a date or timestamp. Amazon Redshift computes the resulting scale dynamically based on the scales of the operands. As for dynamic conversion, it's like this: EXTRACT ('epoch' FROM CONVERT_TIMEZONE ('GMT','GMT -1',your_column::timestamp))Method 2. datediff 関数のデフォルトの列名は date_add です。日付の値に使用するデフォルトのタイムスタンプは 00:00:00 です。 次の例では、タイムスタンプを指定しない日付の値に 30 分を追加します。Amazon Redshift doesn't validate POSIX-style time zone specifications, so it is possible to set the time zone to an invalid value. The Athena Redshift connector performs predicate pushdown to decrease the data scanned by the query. DATEDIFF returnes the number of full weeks between the datetime values. An identifier literal or string of the specific part of the date value (for example, year, month, or day) that the function operates on. DATE: Dates without the time part. 0. SELECT iv. The other is where the date is more than or equal to the date 3 months ago; so using the same data again would be 30 January to 30 April inclusive. Arguments. Here is the code used in RS. 1. 以下示例查找过去日期和今天日期中的文本值之间的差异（以季度数为单位）。此示例假定当前日期为 2008 年 6 月 5 日。您可以可以用全名或缩写来命名日期部分。datediff 函数的默认列名称为 date_diff。However, you can query any catalog table or view openly if your query does not involve a join to an Amazon Redshift table. by the way, Just new in DBeaver. dd/mm/yyyy), which makes me suspect that your SQL implementation is set up to parse them as some other format (e. Create 1 day ranges new_start and new_end. Syntax DATEDIFF(endDate string, startDate string) → integer endDate: A DATE or TIMESTAMP expression. CURRENT_DATE returns 10/01/08, not. The following query uses the ADD_MONTHS function inside a TRUNC function. Before we get started, a few basics. SELECT (EXTRACT(epoch from age('2017-6-15', now())) / 86400)::int In Redshift, you can use date_trunc() (See online documentation). Improve this answer. Here its 0. Returns the difference between two dates or times for a given date. month, week or hour, and it will return the truncated timestamp or interval with the level of precision. AWS Redshift was one of the first cloud data warehouses to become available on the market, officially launching in 2013. Like most other SQL functions, you need to pass in arguments; for the DATE_PART function, you’ll pass in a date/timestamp/date field that you want to extract a date part from and specify the part you want removed. 00. Amazon Redshift. Name and group by those, and also get the minimum Order. SQL Server DATEPART() function overview. DATEPART ( date_part ,. e. This will draw the distinct pairs of id's and dates out and rejoin them onto the dataset only where the joined dates are earlier than the row in question. I know that I can do another query to then get the max ID but I would ideally like to just go by timestamp. SQL Server: -- Get difference in days SELECT DATEDIFF (dd, '2022-09-01', '2022-09-05'); # 4. The right way to subtract between datetimes is: select datediff (seconds, table1. Syntax TO_DATE ( string, format) TO_DATE ( string, format, is_strict) Arguments string A string to be converted. Specify an OLE DB server type other. DIFFERENCE function. Excluding only weekends doesn't work for business purposes. Internally Data Services reads both the date and the time when it runs a sysdate function. Redshift will place the query in a paused state temporarily. Use CASE where a SQL expression is valid, such as in a SELECT command. Redshift query between date. SELECT DATEDIFF (day, '2019-12-05 08:09:55', GETDATE ()); Result:. its a subtraction between 2 different tables that i need in business days. 具体而言，DATEDIFF 确定在两个表达式之间交叉的日期部分边界的数量。. Amazon Redshift accepts different date formats, including ISO date time strings. The ADD_MONTHS function adds 12 months to each value from the CALDATE column. id and date_diff('day', t. To view a list of supported time zone names, run the following command. Datetime types. usa_end_datetime::timestamp) * 1. Redshift provides 2 kinds of node resizing features: Elastic resize; Classic resize; Elastic Resize. I am trying to calculate the number of days between two dates. The DATETIME_DIFF arguments are datetimes, not dates; Snowflake, Redshift, and Databricks’ DATEDIFF functions support multiple date types such as dates and timestamps. If you have 2 integers that represent years, and you want to know the difference between them, then just treat them like integers and use the - operator. Question: How can I take a start timestamp (created_at) and end timestamp (ended_at) and add a column that adds 1 month to the start timestamp until the end timestamp. The rows will be skipped, but you can look in STL_LOAD_ERRORS - Amazon Redshift to view the errors. Date_trunc Function. This question is in a collective: a subcommunity defined by tags with relevant content and experts. 0 is for 1/1/1900, and getdate is the current date --(i used a set date bc dates will change as this post gets older). It assumes that two given dates are business days. The best solution is to combineto use Redshift function DATEDIFF. Redshift Date functions: LAST_DATE function. Actual behavior It is throwing a parser exception Token ')' expected: [1:209]. 000','2014-09-23 01:23:45. DATEDIFF. 90) within group (order by datediff(day, START_DATE, END_DATE) I am guessing that the problem is the date difference. e. The default column name for a DATEADD function is DATE_ADD. Redshift Date Time Operations. The DATEPART() function returns an integer which is a part of a date such as a day, month, and year. This example uses the current date to find the difference between the current date and a specific date. Redshift first requires the user to set up collections of servers called clusters; each cluster runs an Amazon Redshift engine and holds one or more datasets. This is actually quite a complex problem because it involves: Hours within a day. When you push the DATE_DIFF() function to Amazon Redshift using a Redshift ODBC connection, the Secure Agent incorrectly returns the difference values. Numeric functions to perform operations on numeric data. Sign up for free to join this conversation on GitHub . This example assumes that the current date is June 5, 2008. The change is at COUNTER ||';';. For example, the join condition pg_database. sql. A date field or a call to another function that outputs a date. For the first day of last month: select date_trunc('month', current_date) - interval '1 month' Or: select date_add(month, -1, date_trunc('month', current_date)) Amazon Redshift is a fast, scalable, secure, and fully managed cloud data warehouse that makes it simple and cost-effective to analyze all your data using standard SQL and your existing ETL (extract, transform, and load), business intelligence (BI), and reporting tools. In Google BigQuery and Amazon Redshift, the <date_part> is passed in as the first argument and the <date/time field> is the second argument. DATEDIFF(MONTH, 0, '2-14-2015') --returns month. datediff () counts the number of boundaries that are crossed between the two date expressions given as second and third argument, expressed in the unit given as first argument. I know this question is a few years old- but I stumbled across it and. Below is the syntax of JSON in redshift are as follows. Snowflake is a complete SaaS offering that requires no maintenance. This case means that if we start at startdate '2036-03-01', and then count -2 days, we reach the enddate of '2036-02-28'. The following code snippet provides an example of this behavior: SELECT datediff (DAYS, '2021-01-01'::DATE, '2021-02-01'::DATE) AS datediff_interval_output , datediff ('day', '2021-01-01. If you're experiencing performance issues in your Amazon Redshift cluster, consider the following approaches: Monitor your cluster performance metrics. amazon-redshift; typecasting-operator; or ask your own question. 1. Amazon Redshift allocates the workload to the cluster nodes and. datepart. ago. In the elastic resize, the cluster will be unavailable briefly. The first expression in a range condition must be the lesser value and the second expression the greater value. It's fairly trivial do something like. . SELECT * FROM tickets t LEFT JOIN d_customer c ON c. asked Oct 30, 2018 at 20:06. 0 Kudos. d[S+] Lists local user created tables, regular views, late-binding views and materialized. The Redshift DATEDIFF function is used to calculate the difference between two date values based on the interval specified using either Years, Months, Days, Weeks, Hours, Minutes, Seconds, Milliseconds, et al. Cells (i, 1). g. how to get datediff of less than 6 days for same equipment. mwdb • 1 yr. Note. It would handle leap years. To find the difference between two dates in the same column, we need two dates from the same column. Consider SQL Server function to calculate the difference between 2 dates in months: SQL Server : -- Difference between Oct 02, 2011 and Jan 01, 2012 in months SELECT DATEDIFF ( month, '2011-10-02', '2012-01-01') ; -- Result: 3. For more information about how Amazon Redshift SQL differs from PostgreSQL, see Amazon Redshift and PostgreSQL. MONTHS_BETWEEN is a good solution to this problem. TIMEZ: Time with time zone info (since time in New York is behind that in Tokyo, for instance, time zones reflect this difference) TIMESTAMP:. datepart. When your query uses multiple federated data sources Amazon Redshift runs a federated subquery for each source. Even then then there were significant differences in the supported SQL because of Redshift's clustered columnar architecture. date 1. sql. Method 2: Querying Data in Redshift using SQL. 3333 etc. you want difference in terms of days. Argomenti. For this example, you create a table with START_DATE and END_DATE columns, insert rows that include null values, then apply an NVL. Public Holiday. person_id. datediff () counts the number of boundaries that are crossed between the two date expressions given as second and third argument, expressed in the unit given as first argument. 0. The. 2) Coalesce – Coalesce is the function name in redshift which returns first not-null value as a result. datetime. The date function used to returns the difference between two date or datetime values as a given unit of duration. Your highlighted WHERE clause logic is comparing timeworkedfrom to a date six months earlier than the first of the current month. Redshift Date functions: DATE_DIFF function. Redshift is a fully managed data warehouse that exists in the cloud. I know that I can do another query to then get the max ID but I would ideally like to just go by timestamp. Amazon Redshift is a fast, fully managed, cloud-native data warehouse that makes it simple and cost-effective to analyze data using standard SQL and your existing business intelligence tools. How to use Redshift DATEDIFF? 0. To use it use the following syntax: DATEDIFF (part, start, end) This is the documentation for the Amazon Redshift Developer Guide - amazon-redshift-developer-guide/r_DATEDIFF_function. You shouldn't be converting to time - it is meant to store a point in time on a single 24h clock, not a duration or interval (even one that is constrained on its own to < 24 hours, which clearly your data is not). Redshift Spectrum scans the files in the specified folder and any subfolders. 9x better. In SQL Server, you can use DATEDIFF function to get the datetime difference in specified units. Data types are declared when tables are created. 0. What is the Amazon Redshift DATEDIFF function? The Amazon Redshift DATEDIFF function returns the difference between the date parts of two date or time. 2 Answers. I know this is a simple question, but I just started to explore Redshift and couldn't google the answer yet. en datediff(&#. Side-note: In Redshift, CHARACTER VARYING is the same as TEXT, so you might as well use TEXT since it is shorter. person_id, MIN(datediff(t1. PostgreSQL - Date Difference in Months. If you want to do it day, do it following way select datediff(day,order_date,complain_date) as diff_in_day from your_table; You could use datediff function to update your table column time_duration. This function was run on 14 Jan which gives the result of 39. mydatetime) AS DateDifference FROM DateCte. 00274 because of the leap year. Snowflake vs Redshift - learn 10 differences between these DW. The time zone for the return value. I need to subtract 5 hours from sysdate in Redshift. ('day',start_time) AS exec_day, status, COUNT(*) AS query_cnt, AVG(datediff (microsecond,start_time,end_time)) AS elapsed_avg FROM sys_query_history WHERE query_type = 'SELECT' AND start_time >= '2022-01-14' AND. select on_call, on_call::int * interval '1 second' from dev_isaac. In case this doesn’t work, reboot your cluster. We named this one. Any user assigned a role with this permission attached must sign in the query editor with temporary credentials. AWS Redshift clusters require some manual maintenance. This function takes two date values and returns the difference between them in the unit specified by the ‘date part’ argument. most_recent) However, I am running into issues where the timestamp is the same. DATEDIFF with datepart function in Redshift SELECT DATEDIFF(year, '2021/08/25', '2027/08/25' ) AS DateDiff; -- Returns 6 DATEDIFF with datepart function equivalent in. createddate, table2. The parameterized snippet below can be used to find the number of weekdays between 2 dates. But on the last day of the week (day Friday), the total number will reflect. 1) Select json_function (name_of_json_column, ‘value of json column’) where condition. SELECT DATEDIFF (day, '2019-12-05 08:09:55', GETDATE ()); Result: 39. The first example in that case is not correct it should start with 6/1/2018 not 5/1/2018. 128-bit signed integers with up to 38 digits of precision. You were missing a closing semicolon inside the UPDATE statement. set timezone to ‘xxx36’; ISO-8601 Offset – The offset from UTC in the form ± [hh]: [mm]. 543081, my output should be 2019-03-01 11:17:57. We named this one. The subfield of a date or time to extract, such as a day, month, year, hour, minute, second, millisecond, or microsecond. The fully timestamp values contains default value as (00) for missing seconds. . The function returns the result of subtracting the second argument from the third argument. Use an interval literal to identify specific periods of time, such as 12 hours or 6 weeks. DATE ()関数 - 日付部分の抽出 時刻情報を除いて、年月日の部分だけを取得したい場合に便利です。. eg: each ndc has fill_nbr = 1 as the initial fill. Saved searches Use saved searches to filter your results more quicklyStrange SQLite does not have a DATEDIFF function. Share. timeworkedfrom >= date_trunc. Hi Team, The formula below was built as a beastmode but would like to move it to dimensions, the backend. Why is. NAME, table2. 3) Select – Select is used to fetch data from table by using a coalesce function in redshift. VARBYTE type. You can create an Amazon Redshift table with a TEXT column, but it is converted to a VARCHAR (256) column that accepts variable-length values with a maximum of 256 characters. id = d. Data warehouses like Redshift and Snowflake have a super useful DATEDIFF function – given two timestamps and a date part (hour, year, week, etc) it'll return how far apart they are. I want to calculate the months_in_inventory by calculating the difference between a fixed_date and the inventory_date. See Presto documentation for date_diff()-- the unit is regular varchar, so it needs to go in single quotes: date_diff('day', ts_from, ts_to) Share. With AUTO distribution, Amazon Redshift assigns an optimal distribution style based on the size of the table data. In my Redshift table I have 2 columns that stores timestamp values: start_date_time and end_date_time. The following example returns the number of tickets sold for each of the last 7 days of the month. How do I go about getting the first date of current year using Redshift? I am familiar with T-SQL/SQL in SSMS but I am not entirely sure how to do this in Redshift. this continues till the end of the week. The default Redshift release format is YYYY. Dalam hal ini, fungsi mengembalikan 1 tahun meskipun fakta bahwa tanggal-tanggal ini hanya terpisah satu hari. If diff is 12 hours, than result should be 0. Again, the expected results would be a value of 1. Returns the count (signed integer) of the specified datepart boundaries crossed between the specified startdate and enddate. If the second date or time is earlier than the first date or time, the result is negative. 7k 2 2 gold badges 53 53 silver badges 83 83 bronze badges. The parameterized snippet below can be used to find the number of weekdays between 2 dates. The default timestamp for a date value is 00:00:00. Storage. most_recent) However, I am running into issues where the timestamp is the same. To be clear, I need any year fraction as well (ie. Expected Results: 12. SUPER type. Our latest blog goes over 5 potential options: 1. In MySQL, you can use TIMESTAMPDIFF function. how to get date difference between two dates using DateDiff Excluding the weekends. inventory_date::date))) * 12 + EXTRACT (month FROM age ('2020. Create timestampdiif function in Redshift. Note that unit values can be different in SQL Server DATEDIFF and MySQL TIMESTAMPDIFF. It appears that Redshift supports two possible functions for computing a time interval distance between two DATE -like objects: DATEDIFF () & date_diff (). The first 6 is the difference (in months) between 01/10/2018 (October 1, 2018) and 30/04/2019 (April 4, 2019). Amazon Redshift supports the comparison operators described in the following table: Value a is less than value b. select datediff (qtr, '1998-07-01', current_date); date_diff ----------- 40 (1 row) En este ejemplo, se unen las tablas SALES y LISTING para calcular cuántos días después de indicarse se vendieron los tickets de los listados 1000 a 1005. This is what i have so far. StartDate = CDate (. Specifically, DATEDIFF determines the number of datepart boundaries that are crossed between two expressions. The arguments are <date1> and <date2>. Learn how to convert timestamps from one time zone to another in Amazon Redshift using the convert_timezone() function. Boolean type. CREATE TABLE ORDERS ( ID INT , PRODUCT CHAR. Sorted by: 0. Photo by Daniele Levis Pelusi / Unsplash. If diff is 12 hours, than result should be 0. I need to find the difference between start_date_time and end_date_time, such that, if difference is 1 day, then result should be 1. Redshift Spectrum reduces the time and effort required to perform analysis. What is the use of DATEDIFF in redshift? Redshift date_trunc. Add a comment. Date functions to manipulate date data types in Redshift. How to use the DATEDIFF function įor the DATEDIFF function, there’s three elements, or arguments, passed in: This post will go over how to use the DATEDIFF function across different data warehouses and how to write more standardized DATEDIFF functions using a dbt macro (or successfully find. Out of curiosity I executed: select datediff(day, getdate(), current_timestamp); and got the following error: function pg_catalog. date_to) * 2) - CASE WHEN DATEPART(DW, evnt.